Show that (cosec θ - cot θ) / sin θ = 1 / (1 + cos θ)
- (a)(i)Show that (cosec θ - cot θ) / sin θ = 1 / (1 + cos θ)[4]
- (a)(ii)Hence solve (cosec θ - cot θ) / sin θ = 5/2 for 180° < θ < 360°.[2]
- (b)Solve tan(3φ - 4) = -1/2 for 0 < φ ≤ π/2 radians.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [M2] 1/sinθ - cosθ/sinθ / sinθ (M1 for either cosecθ - cotθ = 1/sinθ - cosθ/sinθ or cosecθ - cotθ / sinθ = (1/sinθ - cotθ)/sinθ or cosecθ - cotθ / sinθ = cosecθ/sinθ - cotθ/sinθ )
- [M1] (1-cosθ)/sin²θ or (1-cosθ)/(1-cos²θ)
- [A1] (1-cosθ) / ((1-cosθ)(1+cosθ)) = 1 / (1+cosθ)
- [B2] awrt 233.1 (with no extras in range) (B1 for cos θ = -3/5 soi)
- [M1] 3φ-4 = tan⁻¹(-1/2) soi
- [A2] awrt 0.132, 1.18 (with no extras in range, A1 for one correct)
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →