Find the number of different arrangements of the books if there are no restrictions.
- (a)(i)Find the number of different arrangements of the books if there are no restrictions.[1]
- (a)(ii)Find the number of different arrangements if the mathematics books have to be kept together.[3]
- (a)(iii)Find the number of different arrangements if the mathematics books have to be kept together and the geography books have to be kept together.[3]
- (b)(i)there are no restrictions,[1]
- (b)(ii)there is at least one woman in the team.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [B1] 40320
- [B1] No. of ways with maths books as 1 unit = 5! or 5×4! or ⁵P₅ or 120
- [B1] No. of ways maths books can be arranged amongst themselves = 4! or ⁴P₄ or 24
- [B1] Total = (5! ×4! oe) = 2880
- [B1] No. of ways with maths books as 1 unit and geography books as 1 unit = 3! or ³P₃ or 3×2! or 6
- [B1] No. of ways maths books can be arranged amongst themselves and geography books can be arranged amongst themselves = 4! ×3! or ⁴P₄ x ³P₃ or 144
- [B1] Total = (3! ×4! ×3! oe) = 864
- [B1] ¹²C₆ = 924
- [M1] Either: 924 – ⁸C₆ For their (i) – the number of teams of just men
- [A1] Total = 896
- [M1] Or: 5M 1W : ⁸C₅ × ⁴C₁ (=224) 4M 2W : ⁸C₄ x ⁴C₂ (= 420) 3M 3W : ⁸C₃ × ⁴C₃ (= 224) 2M 4W : ⁸C₂x⁴C₄ (= 28) For a complete method
- [A1] Total = 896
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →