Answer only one of the following two alternatives.
- EITHER (i)The diagram represents a company logo ABCDA, consisting of a sector OABCO of a circle, centre O and radius 6 cm, and a triangle AOD. Angle AOC = 0.8π radians and C is the mid-point of OD. Find the perimeter of the logo,[7]
- EITHER (ii)the area of the logo.[5]
- OR (i)The diagram shows part of the curve y = x³ – 6x² + 8x + 5. The tangent to the curve at the point P(1, 8) cuts the curve at the point Q. Show that the x-coordinate of Q is 4.[6]
- OR (ii)Find the area of the shaded region.[6]
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Mark scheme
Marking points from the official mark scheme (May/June 2010). The mark or mark type is shown in brackets.
- [M1] EITHER (i) Sector angle = 1.2π
- [A1] OD = 12
- [M1] AD² = 12² + 6² - 2×12×6 cos 0.8π
- [A1] AD=17.2
- [M1] Uses s = 6×(1.2π)= (7.2π) (or 22.6)
- [M1] Complete plan (AD+re+6) or (17.2+7.2π + 6)
- [A1] 45.8
- [M1] EITHER (ii) AOD = 1/2 × 6 × 12 sin 0.8π
- [A1] 21.2
- [M1] Uses A = 1/2 × 6² × (1.2π)
- [A1] 21.6π or 67.8 or 67.9
- [A1] 89.0 or 89
- [M1A1] OR (i) dy/dx = 3x² - 12x +8
- [A1] gradient tangent = -1
- [A1] tangent y - 8 = −1(x – 1) or x + y = 9
- [M1] Valid method (e.g. substitute x = 4 in both)
- [A1] Valid conclusion (e.g. y = 5 in both)
- [M1A1] OR (ii) ∫y dx = x⁴/4 - 2x³ + 4x² + 5x
- [M1] Uses limits F(4) – F(1)
- [A1] 12.75
- [B1] Subtracts from area of trapezium (19.5)
- [A1] 6.75
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