It is given that p(x) = x³ + ax² + bx – 48. When p(x) is divided by x – 3 the remainder is 6. Given that p'(1) = 0, find the value of a and of b.
- It is given that p(x) = x³ + ax² + bx – 48. When p(x) is divided by x – 3 the remainder is 6. Given that p'(1) = 0, find the value of a and of b.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [M1] attempt to find p(3)
- [A1] 3a+b=9 oe
- [M1] attempt to differentiate and find p'(1)
- [A1] 2a+b=-3 oe
- [A1] a =12, b = -27 for both
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