The point A, where x = 0, lies on the curve y = ln(4x² + 3)/(x – 1). The normal to the curve at A meets the x-axis at the point B.
- (i)Find the equation of this normal.[7]
- (ii)Find the area of the triangle AOB, where O is the origin.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2015). The mark or mark type is shown in brackets.
- [M1] differentiation of a quotient (or product)
- [B1] correct differentiation of ln(4x² + 3)
- [A1] all else correct
- [B1] for y value
- [M1] valid attempt to obtain gradient of the normal
- [M1] attempt at normal equation must be using a perpendicular
- [A1] cao (Allow y = 0.91x-1.1)
- [M1] valid attempt at area
- [A1] Area = ±0.66 or ±0.67 or awrt these or (1/2)(ln3)²
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