The function f is defined, for 0° < x < 360°, by f(x) = 1 + 3 cos 2x.
- (a)(i)Sketch the graph of y = f(x) on the axes below.[4]
- (a)(ii)State the amplitude of f.[1]
- (a)(iii)State the period of f.[1]
- (b)Given that cos x = p, where 270° < x < 360°, find cosec x in terms of p.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2013). The mark or mark type is shown in brackets.
- [B1] (a)(i) shape; cosine curve - must be approaching a turning point
- [B1] (a)(i) be centred on y = 1
- [B1] (a)(i) clear intent to have min at -2 and max at 4
- [B1] (a)(i) 2 cycles
- [B1] (a)(ii) 3
- [B1] (a)(iii) 180
- [B1] (b) cosec x = 1/sin x soi
- [B1] (b) sin x = √(1 - cos² x) or √(1 - p²)
- [B1] (b) -1 / √(1 - p²) o.e.
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