Skip to main content
O-LevelAdditional MathematicsTrigonometry4037/22 · May/June 2013 · Q109 Marks

The function f is defined, for 0° < x < 360°, by f(x) = 1 + 3 cos 2x.

  1. (a)(i)Sketch the graph of y = f(x) on the axes below.[4]
  2. (a)(ii)State the amplitude of f.[1]
  3. (a)(iii)State the period of f.[1]
  4. (b)Given that cos x = p, where 270° < x < 360°, find cosec x in terms of p.[3]

This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.

Mark scheme

Marking points from the official mark scheme (May/June 2013). The mark or mark type is shown in brackets.

  1. [B1] (a)(i) shape; cosine curve - must be approaching a turning point
  2. [B1] (a)(i) be centred on y = 1
  3. [B1] (a)(i) clear intent to have min at -2 and max at 4
  4. [B1] (a)(i) 2 cycles
  5. [B1] (a)(ii) 3
  6. [B1] (a)(iii) 180
  7. [B1] (b) cosec x = 1/sin x soi
  8. [B1] (b) sin x = √(1 - cos² x) or √(1 - p²)
  9. [B1] (b) -1 / √(1 - p²) o.e.

Write your answer and get it marked

On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.

Sign up free →

About this question

Topic
Trigonometry, O-Level Additional Mathematics (syllabus 4037). Structured question, 9 marks.
Source
O-Level Additional Mathematics, May/June 2013 Paper 2 Variant 2, question 10.

Questions and mark schemes are from past examination papers and remain the copyright of the exam board. How Oracle Prep builds its content

Related Additional Mathematics questions

© 2026 Oracle Prep