Variables x and y are such that, when y² is plotted against secx, a straight line graph passing through the points (2.4, 1.6) and (1.3, 3.8) is obtained. [Figure 4]
- (i)Express y² in terms of secx.[3]
- (ii)Hence find the exact value of cosx when y = 2.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2010). The mark or mark type is shown in brackets.
- B1 for gradient
- M1 for correct attempt to link y² and sec x
- A1
- DM1 for attempt to solve their equation using y = 2
- A1
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