Answer only one of the following two alternatives. EITHER The diagram shows part of the curve y = sin(½x). The tangent to the curve at the point P (3π/2, √2/2) cuts the x-axis at the point Q. [Figure 11.1]
- (i)Find the coordinates of Q.[4]
- (ii)Find the area of the shaded region bounded by the curve, the tangent and the x-axis.[7]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2012). The mark or mark type is shown in brackets.
- [M1] (i) dy/dx = ½ cos(½x)
- [A1] (i) Gradient tangent = -√2/4 or -0.35...
- [M1] (i) y - √2/2 = -√2/4 (x - 3π/2)
- [A1] (i) y = 0, x = 3π/2 + 2 or 6.71
- [B1] (ii) ∫sin(½x)dx = -2cos(½x)
- [B1] (ii) Identify 2π
- [M1] (ii) Use limits of 1.5π and (2π) on -2cos(½x) (2-√2 or 0.586)
- [M1] (ii) Attempt at area of triangle ½ × (base × height)
- [M1] (ii) (= √2/2 = 0.707)
- [M1] (ii) Idea of area of triangle subtract area under curve.
- [M1] (ii) Plan completely correct
- [A1] (ii) 3√2/2 - 2 or 0.121
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →