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O-LevelAdditional MathematicsTrigonometry4037/22 · Oct/Nov 2025 · Q1110 Marks

Solve the equation tan²2x-4 tan2x = 0 for 0° ≤ x ≤ 180°.

  1. (a)Solve the equation tan²2x-4 tan2x = 0 for 0° ≤ x ≤ 180°.[4]
  2. (b)Solve the equation cosec(y+1.2) = 4, where y is in radians and -5 < y < 2.[6]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2025). The mark or mark type is shown in brackets.

  1. [M1] (a) [tan2x = 0 →] Any two of 2x = 0, 180, 360
  2. [A1] (a) [x = ] 0, 90, 180 nfww and no extras from tan 2x = 0 in range 0 ≤ x ≤180
  3. [M1] (a) [tan 2x = 4 →] 2x = 75.96... or 255.96...
  4. [A1] (a) 38 [.0] or 37.98[18...] isw
  5. [A1] (a) 128 [.0] or 127.98[18...] isw and no extras from tan 2x = 4 in range 0 ≤ x ≤180
  6. [B1] (b) sin(y+1.2) = 1/4
  7. [M2] (b) Two correct values for y + 1.2 soi
  8. [M1] (b) for any one correct value for y + 1.2
  9. [A3] (b) -0.947 or -0.9473[19...] isw
  10. [A2] (b) for two correct angles, ignoring extras in range
  11. [A1] (b) for one correct angle, ignoring extras in range
  12. [A3] (b) 1.69 or 1.688[91...] isw
  13. [A3] (b) -4.59 or -4.594[27...] isw
  14. [A3] (b) and no others in range –5 < y < 2

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About this question

Topic
Trigonometry, O-Level Additional Mathematics (syllabus 4037). Structured question, 10 marks.
Source
O-Level Additional Mathematics, Oct/Nov 2025 Paper 2 Variant 2, question 11.

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