Given that y = x cos 2x, find dy/dx.
- (a)Given that y = x cos 2x, find dy/dx.[2]
- (b)Hence find ∫ x sin 2x dx.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2025). The mark or mark type is shown in brackets.
- [M1] (a) [1] cos2x + x(-2sin2x) oe, isw, nfww
- [M1] (a) for d/dx(cos2x) = -2sin2x soi or M1 FT for correct structure of product rule FT their(-2 sin 2x)
- [A1] (a) implied by 2 marks
- [M3] (b) -1/2 x cos2x + 1/4 sin2x + c oe, isw, nfww
- [M2] (b) for -2∫xsin 2x dx = x cos 2x - 1/2 sin 2x +c or for -1/2 xcos2x + ksin2x + c, where k > 0 oe, or for ∫xsin2x dx = -1/2 x cos2x + ∫1/2 cos 2x dx oe,
- [M1] (b) for -2∫xsin 2x dx = x cos2x - ∫cos 2x dx or 2∫xsin 2x dx = -xcos2x + ∫cos2x dx or xcos2x = ∫cos2x dx + ∫-2xsin2xdx oe, soi
- [A1] (b) implied by 4 marks
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →