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O-LevelAdditional MathematicsPermutations and combinations4037/22 · Oct/Nov 2022 · Q66 Marks

A 4-digit code is to be formed using 4 different numbers selected from 2, 3, 4, 5, 6, 7, 8 and 9. Find how many possible codes there are if the code forms

  1. (a)a number that is odd and greater than 5000,[3]
  2. (b)a number greater than 5000 with a last digit that is prime.[3]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2022). The mark or mark type is shown in brackets.

  1. [M2] e.g. [starts with 5, 7, 9 and ends in 3 or two of 5, 7, 9] 3 × 6 × 5 × 3 or 270
  2. [M2] and [starts with 6, 8 and ends in 3,5,7, 9] 2 × 6 × 5 × 4 or 240
  3. [M2] OR [ends with 3 and starts with 5, 6, 7, 8, 9] 5 × 6 × 5 × 1 or 150
  4. [M2] and [ends with 5, 7, 9 and starts with 6, 8 or two of 5, 7, 9] 4 × 6 × 5 × 3 or 360
  5. [M1] for a partially correct method equivalent to one of the above two steps
  6. [A1] 510
  7. [M2] e.g. [starts with 5, 7 and ends with 2, 3 and 5 or 7] 2 × 6 × 5 × 3 = 180
  8. [M2] and [starts with 6, 8, 9 and ends with 2, 3, 5, 7] 3 × 6 × 5 × 4 = 360
  9. [M2] OR [ends with 2, 3 and starts with 5, 6, 7, 8, 9] 5 × 6 × 5 × 2 or 300
  10. [M2] and [ends with 5, 7 and starts with 6, 8, 9 and 5 or 7] 2 × 6 × 5 × 4 or 240
  11. [M1] for a partially correct method equivalent to one of the above two steps
  12. [A1] 540

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About this question

Topic
Permutations and combinations, O-Level Additional Mathematics (syllabus 4037). Structured question, 6 marks.
Source
O-Level Additional Mathematics, Oct/Nov 2022 Paper 2 Variant 2, question 6.

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