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O-LevelAdditional MathematicsPermutations and combinations4037/12 · Oct/Nov 2021 · Q88 Marks

A 5-digit number is made using the digits 0, 1, 4, 5, 6, 7 and 9. No digit may be used more than once in any 5-digit number. Find how many such 5-digit numbers are even and greater than 50000.

  1. (a)A 5-digit number is made using the digits 0, 1, 4, 5, 6, 7 and 9. No digit may be used more than once in any 5-digit number. Find how many such 5-digit numbers are even and greater than 50000.[3]
  2. (b)The number of combinations of n objects taken 4 at a time is equal to 6 times the number of combinations of n objects taken 2 at a time. Calculate the value of n.[5]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2021). The mark or mark type is shown in brackets.

  1. [B1] Starting with a 6: 120 ways
  2. [B1] Starting with 5, 7 or 9: 540 ways
  3. [B1] Total 660
  4. [(B1)] Or Alternative 1 Ending with a 6: 180 ways
  5. [(B1)] Ending with 0 or 4: 480ways
  6. [(B1)] Total 660
  7. [(B1)] Or Alternative 2 11 ways of obtaining even 5-digit numbers which start with 5, 6, 7, 9
  8. [(B1)] ⁵P₃ ways of arranging remaining 3 digits: 60
  9. [(B1)] 11×60=660
  10. [(B2)] Or Alternative 3 Total arrangements ⁷P₅ minus (all odds + evens starting with 1 + evens starting with 0 or 4) = 2520 – (1440 + 180 + 240)
  11. [(B1)] 660
  12. [B1] n!/((n-4)!4!) = 6n!/((n-2)!2!)
  13. [B1] for (n-2)(n-3)
  14. [B1] for 72
  15. [M1] for correct attempt to form and solve a quadratic equation
  16. [A1] for n = 11 only

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About this question

Topic
Permutations and combinations, O-Level Additional Mathematics (syllabus 4037). Structured question, 8 marks.
Source
O-Level Additional Mathematics, Oct/Nov 2021 Paper 1 Variant 2, question 8.

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