f(x) = x²+2x-3 for x≥-1
- (a)Given that the minimum value of x² + 2x-3 occurs when x =-1, explain why f(x) has an inverse.[1]
- (b)On the axes below, sketch the graph of y = f(x) and the graph of y = f¯¹(x). Label each graph and state the intercepts on the coordinate axes.[4]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- B1 It is a one-one function because of the given restricted domain or because x ≥ −1
- B1 for y = f(x) for x >−1 only
- B1 for 1 on x-axis and –3 on y-axis for y = f(x)
- B1 for y = f¯¹(x) as a reflection of y = f(x) in the line y = x, maybe implied by intercepts with axes
- B1 for 1 on y-axis and -3 on x-axis for y = f¯¹(x)
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →