A power supply and a solar cell are compared using the potentiometer circuit shown. [Figure 35.1] The e.m.f. produced by the solar cell is measured on the potentiometer. The potentiometer wire PQ is 100.0 cm long and has a resistance of 5.00 Ω. The power supply has an e.m.f. of 2.000 V and the solar cell has an e.m.f. of 5.00 mV. Which resistance R must be used so that the galvanometer reads zero when PS = 40.0 cm?
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B: 795 Ω
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