Answer all the questions in the spaces provided. (a) Define gravitational potential at a point. (b) TESS is a satellite of mass 360kg in a circular orbit about the Earth as shown in Fig. 1.1. [Figure 1.1] The radius of the Earth is 6.4 × 10⁶m and the mass of the Earth, considered to be a point mass at its centre, is 6.0 × 10²⁴ kg.
- (a)Define gravitational potential at a point.[2]
- (b)(i)It takes TESS 13.7 days to orbit the Earth. Show that the radius of orbit of TESS is 2.4 × 10⁸ m.[3]
- (b)(ii)Calculate the change in gravitational potential energy between TESS in orbit and TESS on a launch pad on the surface of the Earth. change in gravitational potential energy = ................................................................ J [3][3]
- (b)(iii)Use the information in (b)(i) to calculate the ratio: gravitational field strength on surface of Earth gravitational field strength at location of TESS in orbit ratio = ........................................................................ [2][2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2020). The mark or mark type is shown in brackets.
- [1] work done per unit mass
- [1] work done moving mass from infinity (to the point)
- [1] gravitational force provides centripetal force
- [1] mv² / r = GMm/r² and v = 2πr / T OR mrω² = GMm/r² and ω = 2π / T OR r³ = GMT² / 4π²
- [1] r³ = 6.67 × 10⁻¹¹ × 6.0 × 10²⁴ × (13.7 × 24 × 3600)² / 4 π² so r = 2.4 × 10⁸ m
- [1] (Ep = −) GMm/r
- [1] work done = GMm / r₁ – GMm / r₂
- [1] = 6.67 × 10⁻¹¹ × 360 × 6.0 × 10²⁴ (1/6.4 × 10⁶ – 1 / 2.4 × 10⁸) = 2.2 × 10¹⁰ J
- [1] g = GM / r²
- [1] ratio = r_TESS² / r_earth² = (2.4 × 10⁸/6.4 × 10⁶)² = 1400
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →