Answer all the questions in the spaces provided. (b) A smooth pebble, made from uniform rock, has the shape of an elongated sphere as shown in [Fig. 1.1]. The length of the pebble is L. The cross-section of the pebble, in the plane perpendicular to L, is circular with a maximum radius r. A student investigating the density of the rock makes measurements to determine the values of L, r and the mass M of the pebble as follows: L = (0.1242 ± 0.0001)m r = (0.0420 ± 0.0004) m M = (1.072 ± 0.001)kg.
- (a)Define density.[1]
- (b)(i)State the name of a measuring instrument suitable for making this measurement of L.[1]
- (b)(ii)Determine the percentage uncertainty in the measurement of r.[1]
- (c)(i)The density ρ of the rock from which the pebble in (b) is composed is given by ρ = Mrⁿ / kL where n is an integer and k is a constant, with no units, that is equal to 2.094. Use SI base units to show that n is equal to –2.[2]
- (c)(ii)Calculate the percentage uncertainty in ρ.[3]
- (c)(iii)Determine ρ with its absolute uncertainty. Give your values to the appropriate number of significant figures.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2021). The mark or mark type is shown in brackets.
- [B1] mass / volume
- [B1] (vernier/digital) calipers
- [A1] percentage uncertainty = (0.0004 / 0.0420) × 100
- [M1] kg m⁻³ = kg × mⁿ / m or kg m⁻³ = kg × mⁿ × m⁻¹
- [A1] -3 = n - 1 and (so) n = –2
- [C1] (Δρ/ρ) = (ΔΜ/ M) + 2(∆r/ r) + (∆L/L)
- [C1] percentage uncertainty = [(0.001 / 1.072) + 2 × (0.0004 / 0.0420) + (0.0001 / 0.1242)] (× 100)
- [A1] = 0.09% + 2 × 0.95%+ 0.08%
- [C1] ρ = (1.072 × 0.0420⁻²) / (2.094 × 0.1242)
- [C1] Δρ = 0.021 × 2337
- [A1] ρ = (2340 ± 50) kg m⁻³
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →