Electromagnetic radiation is incident on a metal surface. It is observed that there is a minimum frequency of electromagnetic radiation below which emission of electrons does not occur. This observation provides evidence for a particulate nature of electromagnetic radiation. The maximum kinetic energy E_MAX of electrons emitted from a metal surface is determined for different wavelengths λ of the electromagnetic radiation incident on the surface. The variation with 1/λ of E_MAX is shown in [Figure 11.1].
- (a)State two other observations associated with photoelectric emission that provide evidence for a particulate nature of electromagnetic radiation.[2]
- (b)(i)Use [Figure 11.1] to determine the threshold frequency f₀.[2]
- (b)(ii)Use the gradient of the line on [Figure 11.1] to determine a value for the Planck constant h. Explain your working.[4]
- (c)The electromagnetic radiation is now incident on a metal with a larger work function energy than the metal in (b). On [Figure 11.1], sketch the variation with 1/λ of E_MAX.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [B2] any two points from: • (maximum) kinetic energy of electrons is independent of intensity • maximum kinetic energy of electrons depends on frequency • no time delay (between illumination and emission)
- [C1] (for EMAX = 0,) 1/λ₀ = 1.93 × 10⁶ (m⁻¹)
- [A1] f₀ = 3.00 x 10⁸ x 1.93 x 10⁶, = 5.8 x 10¹⁴ Hz
- [C1] hc / λ = Φ + EMAX
- [C1] hc = gradient
- [M1] gradient = e.g. [(0.40 – 0.20) × 1.60 × 10⁻¹⁹] / [(2.25 – 2.09) × 10⁶] (working needed), (= 2.0 × 10⁻²⁵)
- [A1] h = (2.0 × 10⁻²⁵) / (3.00 × 10⁸) = 6.7 × 10⁻³⁴ J s (both working and answer needed)
- [B1] straight line with same gradient as the original
- [B1] straight line with x-axis intercept greater than 1.93 × 10⁶ m⁻¹
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