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A-LevelPhysicsWaves9702/23 · Oct/Nov 2017 · Q411 Marks

(a) By reference to the direction of propagation of energy, explain what is meant by a longitudinal wave. (b) A car horn emits a sound wave of frequency 800 Hz. A microphone and a cathode-ray oscilloscope (c.r.o.) are used to analyse the sound wave. The waveform displayed on the c.r.o. screen is shown in Fig. 4.1. [Figure 4.1] Determine the time-base setting, in s cm⁻¹, of the c.r.o. (c) The intensity I of the sound at a distance r from the car horn in (b) is given by the expression I = k/r² where k is a constant. Fig. 4.2 shows the car in (b) on a road. [Figure 4.2] An observer stands at point O. Initially the car is parked at point X which is 120m away from point O. The car then moves directly towards the observer and stops at point Y, a distance of 30 m away from O. The car horn continuously emits sound when the car is moving between points X and Y.

  1. (a)By reference to the direction of propagation of energy, explain what is meant by a longitudinal wave.[1]
  2. (b)A car horn emits a sound wave of frequency 800 Hz. A microphone and a cathode-ray oscilloscope (c.r.o.) are used to analyse the sound wave. The waveform displayed on the c.r.o. screen is shown in Fig. 4.1. [Figure 4.1] Determine the time-base setting, in s cm⁻¹, of the c.r.o.[3]
  3. (c)(i)The sound wave at point O has amplitude A_X when the car is at X and has amplitude A_Y when the car is at Y. Calculate the ratio A_Y / A_X.[3]
  4. (c)(ii)1the minimum wavelength of the sound detected by the observer,[2]
  5. (c)(ii)2the maximum speed of the car.[2]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.

  1. 4(a) displacement of particles/vibration(s)/oscillation(s) is parallel to/along the direction of energy/propagation B1
  2. 4(b) period = 1/800 (= 1.25 × 10⁻³s) C1 time-base setting = 1.25 x 10⁻³/2.5 C1 = 5.0 × 10⁻⁴ s cm⁻¹ A1
  3. 4(c)(i) I ∝ A² C1 (I_X/I_Y =) [r_Y/r_X]² = [A_X / A_Y]² C1 ratio A_Y/A_X = 120/30 A1 = 4.0
  4. 4(c)(ii)1. v = fλ C1 minimum λ = 330 / (800 + 16) = 0.40 m A1
  5. 4(c)(ii)2. f_o / f_s = v / (V-V_s) C1 816/800 = 330 / (330 – v_s) A1 v_s = 6.5 m s⁻¹

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About this question

Topic
Waves, A-Level Physics (syllabus 9702). Structured question, 11 marks.
Source
A-Level Physics, Oct/Nov 2017 Paper 2 Variant 3, question 4.

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