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A-LevelPhysicsElectric fields9702/42 · Feb/Mar 2018 · Q79 Marks

(a) State what is meant by electric potential at a point. (b) The centres of two charged metal spheres A and B are separated by a distance of 44.0 cm, as shown in [Figure 7.1]. Point P is a distance x from the centre of sphere A. The variation with distance x of the electric potential V at point P is shown in [Figure 7.2]. (i) Use [Figure 7.2] to state and explain whether the two spheres have charges of the same, or opposite, sign. (ii) A positively-charged particle is at rest on the surface of sphere A. The particle moves freely from the surface of sphere A to the surface of sphere B. 1. Describe qualitatively the variation, if any, with distance x of the speed of the particle as it moves from x = 12 cm to x = 25 cm passes through x = 26 cm moves from x = 27 cm to x = 31 cm reaches x = 32 cm 2. The particle has charge 3.2 × 10⁻¹⁹ C and mass 6.6 × 10⁻²⁷ kg. Calculate the maximum speed of the particle. speed = .............................................................. ms⁻¹

  1. (a)State what is meant by electric potential at a point.[2]
  2. (b)(i)Use Fig. 7.2 to state and explain whether the two spheres have charges of the same, or opposite, sign.[1]
  3. (b)(ii)1.Describe qualitatively the variation, if any, with distance x of the speed of the particle as it moves from x = 12 cm to x = 25 cm passes through x = 26 cm moves from x = 27 cm to x = 31 cm reaches x = 32 cm[4]
  4. (b)(ii)2.The particle has charge 3.2 × 10⁻¹⁹ C and mass 6.6 × 10⁻²⁷ kg. Calculate the maximum speed of the particle. speed = .............................................................. ms⁻¹[2]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2018). The mark or mark type is shown in brackets.

  1. [B1] work done per unit charge
  2. [B1] (work done) moving positive charge from infinity (to the point)
  3. [B1] potential always same sign / potential is always positive so same sign of charge
  4. [B1] from x = 12 cm to x = 25 cm: speed increases and from x = 27 cm to x = 31 cm: speed decreases
  5. [B1] (from x = 12 cm to x = 25 cm: speed increases) at decreasing rate or (from x = 27 cm to x = 31 cm: speed decreases) at increasing rate
  6. [B1] at x = 26 cm: speed maximum
  7. [B1] at 32 cm: speed still decreasing
  8. [C1] q ΔV = ½mv²
  9. [A1] 3.2 × 10⁻¹⁹ × (2.14 – 1.43) × 10⁴ = ½ × 6.6 × 10⁻²⁷ × v²
  10. [A1] v² = 6.88 × 10¹¹
  11. [A1] v = 8.3 x 10⁵ m s⁻¹ (8.30)

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About this question

Topic
Electric fields, A-Level Physics (syllabus 9702). Structured question, 9 marks.
Source
A-Level Physics, Feb/Mar 2018 Paper 4 Variant 2, question 7.

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