A student uses a diffraction grating to determine the wavelength of visible light from a source. The diffraction grating has 300 lines per mm. The student measures the angle θ of each order n of the intensity maxima. A graph of n against sin θ is plotted. The line of best fit for the plotted points is shown and has gradient G. [Diagram shows a graph of n (y-axis) against sin θ (x-axis), a straight line passing through the origin with positive gradient G.] Which expression represents the wavelength, in m, of the visible light in terms of G?
✓ Correct Answer
The correct answer is C. This question tests the candidate's understanding of superposition within the Physicssyllabus. The examiner's mark scheme requires...
📋 Examiner Report & Trap Analysis
Common mistake: 62% of candidates selected the distractor because they confused... The examiner specifically designed this question to test whether students can differentiate between... To secure full marks, candidates must demonstrate...
Unlock the Examiner's Answer
Sign up for free to reveal the correct answer, the official mark scheme breakdown, and the examiner trap analysis for this question.
Sign Up Free to Unlock →Join thousands of Cambridge students already using Oracle Prep