An electron is travelling at speed v in a straight line in a vacuum. It enters a uniform magnetic field of flux density 8.0 × 10⁻⁴ T. Initially, the electron is travelling at right angles to the magnetic field, as illustrated in Fig. 9.1. The path of the electron in the magnetic field is an arc of a circle of radius 6.4 cm. A uniform electric field is now applied in the same region as the magnetic field. The electron passes undeviated through the region of the two fields, as illustrated in Fig. 9.2. [Figure 9.1] [Figure 9.2]
- (a)(i)State and explain the direction of the magnetic field.[2]
- (a)(ii)Show that the speed v of the electron is 9.0 × 10⁶ m s⁻¹.[3]
- (b)(i)On Fig. 9.2, mark with an arrow the direction of the uniform electric field.[1]
- (b)(ii)Use data from (a) to calculate the magnitude of the electric field strength.[2]
- (c)The electron in (b) is now replaced by an α-particle travelling at the same speed v along the same initial path as the electron. Describe and explain the shape of the path in the region of the magnetic and electric fields.[2]
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Mark scheme
Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.
- [1] force is downwards/down the page
- [1] current is (right) to left
- [1] by left-hand rule, field is into plane of paper
- [1] magnetic force provides the centripetal force
- [1] Bqv = mv² / r
- [1] v = Bqr / m
- [1] = (8.0 × 10⁻⁴ × 1.60 × 10⁻¹⁹ × 6.4 × 10⁻²) / (9.11 × 10⁻³¹)
- [1] = 9.0 x 10⁶ m s⁻¹
- [1] arrow showing field direction down the page
- [1] Bqv = Eq
- [1] v = E / B
- [1] E = 9.0 x 10⁶ x 8.0 × 10⁻⁴
- [1] = 7.2 x 10³ N C⁻¹
- [1] straight line/undeviated
- [1] condition for no deflection depends only on v
- [1] condition for no deflection does not depend on m or q
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