The velocity of a particle moving in a straight line at time t seconds after leaving a fixed point O is vms⁻¹. The diagram shows a velocity-time graph which models the motion of the particle from t = 0 to t = T. The graph consists of four straight line segments. The particle accelerates from rest to a speed of V ms⁻¹ over a period of 4 s, and then decelerates at 5/3 ms⁻² to instantaneous rest over a period of 6 s. The particle then travels back towards O, reaching a maximum speed of 3 ms⁻¹ before coming to rest at time t = T. [Figure 1]
- (a)Find the value of V.[2]
- (b)Given that the total distance travelled by the particle from t = 0 to t = T is 68m, find the value of T.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [M1] Use of v=u+at or use of acceleration is gradient of the line
- [A1] Make sure that 10 comes from a correct initial equation or equivalent, if not then A0, e.g. (0-V)/(10-4) = 5/3 leading to V=10 is M1A0.
- [B1FT] SOI [If correct distance is 50 m.]
- [M1] Use distance (68) is total area under graph. Their 50 must be from 5*their|V|. Allow with -3. Allow 1/2*X*3 + 1/2*10*their|V|=68 and use of T=X+10.
- [A1] WWW
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