[Figure 1] shows an open tank in the shape of a triangular prism. The vertical ends ABE and DCF are identical isosceles triangles. Angle ABE = angle BAE = 30°. The length of AD is 40 cm. The tank is fixed in position with the open top ABCD horizontal. Water is poured into the tank at a constant rate of 200 cm³ s⁻¹. The depth of water, t seconds after filling starts, is h cm (see [Figure 2]).
- (i)Show that, when the depth of water in the tank is h cm, the volume, V cm³, of water in the tank is given by V = (40√3)h².[3]
- (ii)Find the rate at which h is increasing when h = 5.[3]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2015). The mark or mark type is shown in brackets.
- [B1] x = h tan 60 or x = h√3 (Any correct unsimplified length)
- [M1] Area = (1/2) × (2x) × h (Correct method for area)
- [A1] V = 40√(3h²) (ag)
- [B1] dV/dh = 80√(3h)
- [B1] dV/dt = 200
- [M1] dh/dt = (dh/dV) × (dV/dt) (M1 must be division, not multiplication)
- [A1] 0.289
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