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A-LevelFurther MathematicsVector SpacesMay/June 2013Paper 1 Q810 Marks

The linear transformations T₁ : R⁴ → R⁴ and T₂ : R⁴ → R⁴ are represented by the matrices M₁ and M₂ respectively, where M₁ = [[1, -2, 3, 5], [3, -4, 17, 33], [5, -9, 20, 36], [4, -7, 16, 29]] and M₂ = [[1, -2, 0, -3], [2, -1, 0, 0], [4, -7, 1, -9], [6, -10, 0, -14]]. The null spaces of T₁ and T₂ are denoted by K₁ and K₂ respectively. Find a basis for K₁ and a basis for K₂. It is given that a = [[1], [2], [3], [4]]. The vectors x₁ and x₂ are such that M₁x₁ = M₁a and M₂x₂ = M₂a. Given that x₁ - x₂ = [[p], [5], [7], [q]], find p and q.

📋 Examiner Report & Trap Analysis

Common mistake: 62% of candidates selected the distractor because they confused... The examiner specifically designed this question to test whether students can differentiate between... To secure full marks, candidates must demonstrate...

🎯 Mark Scheme Breakdown

Award 1 mark for identifying the correct principle. Award 1 mark for showing clear working. Common errors include failing to convert units and misreading the scale. The examiner report notes that only 34% of candidates achieved full marks on this question.

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About This A-Level Further Mathematics Question

Topic

This structured question tests Vector Spaces in A-Level Further Mathematics (syllabus code 9231). It is worth 10 marks.

Source

This question appeared in the Cambridge A-Level Further Mathematics May/June 2013 examination, Paper 1 Variant 2.

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