Evaluate ∫₀^(π/2) x sin x dx. Given that I_n = ∫₀^(π/2) xⁿ sin x dx, prove that, for n > 1, I_n = n(π/2)ⁿ⁻¹ – n(n - 1)I_n₋₂. By first using the substitution x = cos⁻¹u, find the value of ∫₀¹ (cos⁻¹u)³ du, giving your answer in an exact form.
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