A-LevelFurther MathematicsLinear Spaces (Matrices and Transformations)Oct/Nov 2015Paper 1 Q710 Marks
The linear transformation T : R⁴ → R⁴ is represented by the matrix M, where M = (1 -2 -3 1 3 -5 -7 7 5 -9 -13 9 7 -13 -19 11) Find the rank of M and a basis for the null space of T. The vector e = (1 2 3 4)ᵀ is denoted by e. Show that there is a solution of the equation Mx = Me of the form X = (a b -1 -1)ᵀ where the constants a and b are to be found.
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