An algorithm has been written in pseudocode to check if a new password is in a list of previously used passwords OldList[] If the password is not found, the new password will be stored at the end of the list to replace "XXXX" already stored there. 01 OUTPUT "Enter your new password " 02 INPUT NewPassword 03 Posn ← 1 04 Found ← FALSE 05 REPEAT 06 IF Password = OldList[Posn] 07 THEN 08 Found ← TRUE 09 ELSE Posn ← Posn + 1 10 ENDIF 11 UNTIL Found AND OldList[Posn] = "XXXX" 12 IF Found 13 THEN 14 OUTPUT "Password has been used before" 15 ELSE 16 INPUT "New password accepted" 17 OldList[Posn] ← NewPassword 18 ENDIF
📋 Examiner Report & Trap Analysis
Common mistake: 62% of candidates selected the distractor because they confused... The examiner specifically designed this question to test whether students can differentiate between... To secure full marks, candidates must demonstrate...
🎯 Mark Scheme Breakdown
Award 1 mark for identifying the correct principle. Award 1 mark for showing clear working. Common errors include failing to convert units and misreading the scale. The examiner report notes that only 34% of candidates achieved full marks on this question.
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