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A-LevelChemistryAnalytical techniques9701/31 · May/June 2018 · Q211 Marks

In this question you will determine the identity of the halogen in compound W. Compound W is the halogenoethanoic acid CH2XCO₂H, where X is a halogen. 4g of W were heated with 250 cm³ of 0.400 moldm-³ aqueous sodium hydroxide. Some of the sodium hydroxide reacted with compound W. The solution that remained after this reaction is FA 3. By titrating FA 3 with hydrochloric acid, you will determine how much of the sodium hydroxide remained after reaction with W. You will then calculate how much sodium hydroxide had reacted and use this to determine the identity of X in CH2XCO2H. FA 3 is aqueous sodium hydroxide after reaction with W. FA 4 is 0.100 mol dm³ hydrochloric acid, HCl. bromophenol blue indicator

  1. (a)Method • Fill the second burette with FA 4. • Rinse the pipette with distilled water followed by a little FA 3. • Use the pipette to transfer 25.0 cm³ of FA 3 into a conical flask. • Add a few drops of bromophenol blue indicator. • Perform a rough titration and record your burette readings in the space below. The rough titre is ................................... cm³. • Carry out as many accurate titrations as you think necessary to obtain consistent results. • Make certain any recorded results show the precision of your practical work. • Record in a suitable form below all of your burette readings and the volume of FA 4 added in each accurate titration. I II III • From your accurate titration results, obtain a suitable value for the volume of FA 4 to be used in your calculations. Show clearly how you obtained this value. 25.0 cm³ of FA 3 required ................................. cm³ of FA 4.[3]
  2. (b)(i)Calculate the number of moles of hydrochloric acid, FA 4, present in the volume calculated in (a). moles of HCl = ................................ mol Hence deduce the number of moles of sodium hydroxide present in 25.0 cm³ of FA 3. moles of NaOH in 25.0 cm³ FA 3 = ................................ mol[1]
  3. (b)(ii)Calculate the number of moles of sodium hydroxide added to the 4 g of W. moles of NaOH added to 4g W = ................................ mol Calculate the number of moles of sodium hydroxide that remain after the reaction with compound W. moles of NaOH remaining after reaction with W = ................................ mol[1]
  4. (b)(iii)Calculate the number of moles of sodium hydroxide that reacted with W. moles of NaOH that reacted with W = ................................ mol Hence calculate the number of moles of W that reacted with this number of moles of sodium hydroxide. moles of W that reacted = ................................ mol[1]
  5. (b)(iv)Use your answer to (iii), and the mass of W used to make FA 3, to calculate the Mr of W. Mr of W = ................................[1]
  6. (b)(v)W is a halogenoethanoic acid, CH2XCO₂H. Use your answer to (iv) to determine the identity of X. Explain how you reached your conclusion.[2]
  7. (c)Apart from any inaccuracies in reading the volumes of solutions, suggest a significant source of error in this practical exercise. Explain how you could minimise this error.[1]
  8. (d)State at what Mr value of W, closest to the one calculated in (b)(iv), you would have concluded that X was a different halogen. Mr value = ................................[1]

Mark scheme

Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.

  1. [1] I Initial and final readings and titre recorded for a minimum of two accurate titre details tabulated (minimum 2 × 3 ‘boxes')
  2. [2] II and III Award II and III for δ ≤ 0.20 cm³ Award II for 0.20 < δ ≤ 0.40 cm³
  3. [1] Correctly calculates moles HCl = vol of FA 2 from (a) × 0.100 / 1000 and moles NaOH are the same
  4. [1] Correctly calculates moles NaOH added to W = 0.40 × 250 ÷ 1000 = 0.10 and moles NaOH remaining = answer to (b)(i) × 10
  5. [1] Correctly uses moles NaOH reacting with W = 1st answer in (b)(ii) – 2nd answer in (b)(ii) (0.10 – 2nd answer in (b)(ii)) and moles W = answer ÷ 2
  6. [1] Correctly uses Mr of W = 4 ÷ answer to (b)(iii)
  7. [1] Expression to show 59 + Ar of X = Mr from (b)(iv)
  8. [1] Identification of X as halogen with nearest Ar to that calculated
  9. [1] Error: Mass was given correct to 1 sig fig / nearest g Modification: Use a more accurate balance or Error: Hydrolysis of halogeno group may be incomplete Modification: Use more concentrated NaOH / heat for longer
  10. [1] If F chosen then 87 If Cl chosen then 86 or 117 If Br chosen then 116 or 163 If I chosen then 162

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About this question

Topic
Analytical techniques, A-Level Chemistry (syllabus 9701). Structured question, 11 marks.
Source
A-Level Chemistry, May/June 2018 Paper 3 Variant 1, question 2.

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