(a) Copper shows typical properties of transition elements, including its behaviour as a catalyst. Complete Table 5.1 to show the total number of unpaired electrons in the 3d and 4s orbitals of an isolated gaseous Cu atom and a Cu2+ ion. [Table 5.1] [1] (b) The 3d orbitals in an isolated Cu2+ ion are degenerate. Complete the diagram to show the relative energies of the 3d orbitals in an isolated Cu2+ ion and in Cu2+ in a tetrahedral complex. [diagram] [2] (c) Explain why transition elements behave as catalysts. [2] (d) CN⁻ is a monodentate ligand. Table 5.2 shows information about two complex ions that contain only CN⁻ ions as ligands. Complete Table 5.2. [Table 5.2] [2] (e) The complex ion [Au(CN)2Br2]⁻ displays geometrical (cis/trans) isomerism. Draw the structure of trans-[Au(CN)2Br2]⁻. State its shape and the Br-Au-Br bond angle. shape Br-Au-Br bond angle = [2] (f) An impure sample of a vanadium(V) compound of mass 0.250 g is dissolved in aqueous acid. This solution contains VO3⁻ ions. An excess of zinc is added to this solution. All the VO3⁻ ions are reduced to V2+ ions and Zn atoms are oxidised to Zn2+ ions. The unreacted zinc is removed and the resulting solution is titrated with acidified MnO4⁻. The end-point is reached when 22.5 cm³ of 0.0750 mol dm⁻³ MnO4⁻ is added. A redox reaction takes place and all the V2+ reacts forming VO3⁻. 3MnO4⁻ + 5V2+ + 3H2O → 3Mn2+ + 5VO3⁻ + 6H+ (i) Calculate the percentage by mass of vanadium in the 0.250 g of impure sample. Assume the impurities do not contain any vanadium ions. Show your working. percentage of vanadium = [3] (ii) Complete the equation for the reaction between acidified VO3⁻ ions and Zn metal. ...... VO3⁻ + ...... Zn + ...... → ...... V²⁺ + ...... Zn²⁺ + ...... [2]
- (a)Complete Table 5.1 to show the total number of unpaired electrons in the 3d and 4s orbitals of an isolated gaseous Cu atom and a Cu2+ ion. [Table 5.1][1]
- (b)The 3d orbitals in an isolated Cu2+ ion are degenerate. Complete the diagram to show the relative energies of the 3d orbitals in an isolated Cu2+ ion and in Cu2+ in a tetrahedral complex. [diagram][2]
- (c)Explain why transition elements behave as catalysts.[2]
- (d)CN⁻ is a monodentate ligand. Table 5.2 shows information about two complex ions that contain only CN⁻ ions as ligands. Complete Table 5.2. [Table 5.2][2]
- (e)The complex ion [Au(CN)2Br2]⁻ displays geometrical (cis/trans) isomerism. Draw the structure of trans-[Au(CN)2Br2]⁻. State its shape and the Br-Au-Br bond angle. shape Br-Au-Br bond angle =[2]
- (f)(i)An impure sample of a vanadium(V) compound of mass 0.250 g is dissolved in aqueous acid. This solution contains VO3⁻ ions. An excess of zinc is added to this solution. All the VO3⁻ ions are reduced to V2+ ions and Zn atoms are oxidised to Zn2+ ions. The unreacted zinc is removed and the resulting solution is titrated with acidified MnO4⁻. The end-point is reached when 22.5 cm³ of 0.0750 mol dm⁻³ MnO4⁻ is added. A redox reaction takes place and all the V2+ reacts forming VO3⁻. 3MnO4⁻ + 5V2+ + 3H2O → 3Mn2+ + 5VO3⁻ + 6H+ Calculate the percentage by mass of vanadium in the 0.250 g of impure sample. Assume the impurities do not contain any vanadium ions. Show your working. percentage of vanadium =[3]
- (f)(ii)Complete the equation for the reaction between acidified VO3⁻ ions and Zn metal. ...... VO3⁻ + ...... Zn + ...... → ...... V²⁺ + ...... Zn²⁺ + ......[2]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2025). The mark or mark type is shown in brackets.
- [1] (a) species | number of unpaired electrons | 3d | 4s Cu | 0 | 1 Cu2+ | 1 | 0
- [2] (b) five 3d orbitals (lines, boxes) in the isolated Cu2+ ion of the same energy splitting: three higher and two lower d orbitals energy of all five d orbitals in complex higher than all d orbitals in isolated ion any two [1], all three [2]
- [2] (c) M1: more than one (stable) oxidation state / exist in variable oxidation states M2: vacant / empty (d) orbitals are energetically accessible OR vacant / empty (d) orbitals can form dative bonds with ligands
- [2] (d) metal ion | coordination number | formula of complex ion | charge of complex ion Ag+ | 2 | Ag(CN)2 | 1- Fe2+ | 6 | Fe(CN)6 | 4- each row [1]
- [2] (e) M1: [drawing shows Au at centre, two CN linear, two Br linear, CN-Au-CN linear, Br-Au-Br linear, trans arrangement for Br or CN] OR [drawing shows Au at centre, two CN opposite, two Br opposite, CN-Au-CN opposite, Br-Au-Br opposite] M2: (shape) square planar AND (bond angle) 180°
- [3] (f)(i) M1: moles MnO4 = 0.075 × 0.0225 = 1.6875 × 10-3 M2: moles V2+ = 5 / 3 × 1.6875 × 10-3 = 2.8125 × 10-3 M3: mass V = 50.9 × 2.8125 × 10–3 = 0.143 g % of V = 0.143 / 0.250 × 100 = 57.3 min 2sf
- [2] (f)(ii) 2VO3 + 3Zn + 12H+ → 2V2+ + 3Zn2+ + 6H2O M1: 2: 3 ratio on both sides M2: rest of the equation correct
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