(a) Define standard cell potential, Ecell. Include a description of standard conditions. [2] (b) The Daniell cell is an electrochemical cell consisting of a Cu2+(aq)/Cu(s) electrode and a Zn2+(aq)/Zn(s) electrode. (i) Draw a labelled diagram of this electrochemical cell. Include all necessary substances and relevant pieces of apparatus needed to measure the Ecell. It is not necessary to state the conditions used. [3] (ii) State the charge carriers that transfer current through the solutions and through the wire. the solutions the wire [1] (iii) The standard electrode potential, E°, for the Zn2+(aq)/Zn(s) electrode is –0.76 V. Water is added to a standard Zn2+(aq)/Zn(s) electrode. The new concentration of Zn2+(aq) is 0.25 moldm⁻³. Use the Nernst equation to calculate the electrode potential, E, for this new Zn2+(aq)/Zn(s) electrode. E (Zn2+(aq)/Zn(s)) = V [2] (c) An electrochemical cell consists of a ZnO/Zn electrode and a MnO2/Mn2O3 electrode in an alkaline electrolyte. The standard cell potential, Ecell, for this cell is +1.47V. The half-equation at each electrode when this cell is discharging is shown. Zn + 2OH¯ → ZnO + H2O + 2e¯ 2MnO2 + H2O + 2e¯ → Mn2O3 + 2OH¯ (i) Use this information to determine the change in oxidation state of manganese when this cell is discharging. from to [1] (ii) Write the equation for the overall reaction that occurs when this cell is discharging. [1] (iii) The E° for the ZnO/Zn electrode is –1.28V. Calculate the standard electrode potential, E°, for the MnO2/Mn2O3 electrode. E° (MnO2/Mn2O3) = V [1]
✓ Correct Answer
The correct answer is —. This question tests the candidate's understanding of electrochemistry within the Chemistrysyllabus. The examiner's mark scheme requires...
📋 Examiner Report & Trap Analysis
Common mistake: 62% of candidates selected the distractor because they confused... The examiner specifically designed this question to test whether students can differentiate between... To secure full marks, candidates must demonstrate...
Unlock the Examiner's Answer
Sign up for free to reveal the correct answer, the official mark scheme breakdown, and the examiner trap analysis for this question.
Sign Up Free to Unlock →Join thousands of Cambridge students already using Oracle Prep