Skip to main content
A-LevelChemistryElectrochemistry9701/12 · Oct/Nov 2024 · Q231 Mark

The name 'chlorate' is used for an anion consisting of chlorine and oxygen only. In a molecule of ICl, the iodine atom has oxidation number x and the chlorine atom has oxidation number y. When ICl is added to H2O, iodine is reduced. 4ICl + 2H2O → 4HCl + O2 + 2I2 Which statement about the value of x or y is correct?

Ax is the same as the oxidation number of Cl in the chlorate ion formed when Cl2(aq) is added to cold NaOH(aq).
Bx is the same as the oxidation number of Cl in the chlorate ion formed when Cl2(aq) is added to hot NaOH(aq).
Cy is the same as the oxidation number of Cl in the chlorate ion formed when Cl2(aq) is added to cold NaOH(aq).
Dy is the same as the oxidation number of Cl in the chlorate ion formed when Cl2(aq) is added to hot NaOH(aq).

✓ Correct answer

A: x is the same as the oxidation number of Cl in the chlorate ion formed when Cl2(aq) is added to cold NaOH(aq).

Practise more questions on this topic

Oracle Prep sorts past-paper questions by topic, so you can drill Electrochemistry and see which topics are most likely to come up next.

Sign up free →

About this question

Topic
Electrochemistry, A-Level Chemistry (syllabus 9701). Multiple choice, 1 mark.
Source
A-Level Chemistry, Oct/Nov 2024 Paper 1 Variant 2, question 23.

Questions and mark schemes are from past examination papers and remain the copyright of the exam board. How Oracle Prep builds its content

Related Chemistry questions

© 2026 Oracle Prep