Lactones are cyclic esters. Under suitable conditions, lactones form from molecules that have both an alcohol and a carboxylic acid functional group. Equation 1 shows an example of the formation of a lactone. [Equation 1 showing a molecule with -OH and -COOH forming a lactone and H₂O] Fig. 5.1 shows the synthesis of lactone P from compound M. [Figure 5.1 showing reaction scheme: M --(KMnO4)--> N(C6H10O3) --(NaBH4)--> 5-hydroxyhexanoic acid --(reaction 3)--> P]
- (a)(i)M reacts with hot concentrated acidified KMnO4(aq) to form N, C₆H₁₀O₃, in reaction 1. Draw the structure of N.[1]
- (a)(ii)N is reduced by NaBH₄ to form 5-hydroxyhexanoic acid in reaction 2. Construct an equation for reaction 2 using molecular formulae. In the equation, use [H] to represent one atom of hydrogen from the reducing agent.[1]
- (a)(iii)Reaction 2 is a nucleophilic addition. Suggest why reaction 2 creates a mixture of two organic compounds.[2]
- (a)(iv)Draw lactone P, the product of reaction 3.[1]
- (b)A student monitors the progress of reaction 2 using infrared spectroscopy. Use Table 5.1 to suggest why it is difficult to distinguish between N and 5-hydroxyhexanoic acid using infrared spectroscopy. [Table 5.1: Functional group and characteristic IR absorption ranges][2]
- (c)Unknown lactone Q is analysed using mass spectrometry. Table 5.2 shows information from the mass spectrum. [Table 5.2: peak (M+, M+1), m/e (72, 73), abundance (95.5, 3.15)] Use these data to deduce the structure of Q. Show your working.[2]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2022). The mark or mark type is shown in brackets.
- [1] HOOC-(CH2)3-CO-CH3
- [1] C6H10O3 + 2[H] → C6H12O3
- [1] M1 (ketone in) N is planar (so can be attacked from either side)
- [1] M2 because different stereoisomers / optical isomers form
- [1] {6-membered lactone ring structure: O-C(=O)-CH2-CH2-CH2-CH2}
- [1] M1 absorptions will overlap / be similar / the same / indistinguishable
- [1] M2 both have some bonds in similar environments owtte
- [1] 100/1.1 - 95.5/3.15 = 3 carbon atoms
- [1] {4-membered lactone ring structure: O-C(=O)-CH2-CH2}
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