(a) The energy cycle shown can be used, along with suitable data, to calculate the enthalpy change of hydration of Ca²⁺(g). Each arrow indicates a transformation, W, X, Y and Z. Each transformation consists of one or more steps. [Figure 3.1] The following data and data from the Data Booklet should be used. electron affinity of Cl(g) = -349 kJ mol-1 enthalpy change of atomisation of Ca(s) = +193 kJ mol-1 enthalpy change of formation of CaCl₂(s) = −795kJ mol-1 enthalpy change of solution of CaCl2(s) = -83 kJ mol-1 enthalpy change of hydration of Cl-(g) = -364 kJ mol-1
- (a)(i)Calculate the value of the enthalpy change corresponding to transformation W. Show your working. enthalpy change W =[2]
- (a)(ii)Use your answer to (a)(i) and other data to calculate the value of the enthalpy change corresponding to transformation Z. enthalpy change Z =[2]
- (a)(iii)Use your answer to (a)(ii) to calculate the enthalpy change of hydration of Ca²⁺(g). enthalpy change of hydration of Ca²⁺(g) =[2]
- (a)(iv)Write an expression, in terms of W, X, Y and/or Z, to show how the enthalpy changes of two of the transformations can be used to calculate the lattice energy of CaCl₂(s). lattice energy of CaCl₂(s) =[1]
- (a)(v)State whether the lattice energy of CaCl₂(s) is more or less exothermic than the lattice energy of MgF2(s). Explain your answer.[1]
- (b)The sulfates of the Group 2 elements vary in solubility down Group 2.
- (b)(i)Give the names of two solutions that could be mixed to form barium sulfate.[1]
- (b)(ii)State and explain how the solubilities of the sulfates of the Group 2 elements vary down Group 2.[4]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [1] (+193 +242 +590 + 1150 + (2x−349))
- [1] answer (+)1477
- [1] (-795 – 83 – 1477)
- [1] -2355
- [1] (-2355 –(2 × −364))
- [1] -1627
- [1] Z-Y OR X-W
- [1] less (exothermic) and both ions (in CaCl2) are larger
- [1] soluble barium salt AND soluble sulfate
- [1] less soluble (down the group)
- [1] ΔHlat and ΔHhyd both decrease down the group
- [1] ΔHhyd decreases more / faster / is dominant factor
- [1] ΔHsol gets less exo / more endo
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