In this experiment you will determine the enthalpy change, ΔH, for the reaction shown. MgO(s) + CO2(g) → MgCO3(s) To do this, you will determine the enthalpy changes for the reactions of magnesium oxide and magnesium carbonate with hydrochloric acid. Excess hydrochloric acid will be used in each reaction. You will then use Hess' Law to calculate the enthalpy change for the reaction. FA 2 is hydrochloric acid, HCl. FA 4 is magnesium oxide, MgO. FA 5 is magnesium carbonate, MgCO3.
- (a)Determination of the enthalpy change for the reaction of magnesium oxide, FA 4, with hydrochloric acid, FA 2 Method • Support a plastic cup in the 250 cm³ beaker. • Use the measuring cylinder to transfer 40 cm³ of FA 2 into the plastic cup. • Measure and record the initial temperature of the solution. • Weigh the container with FA 4. Record the mass. • Add all the FA 4 from the container to the FA 2 in the plastic cup. • Stir constantly until the maximum temperature is reached. • Measure and record the maximum temperature. • Weigh the container with any FA 4 remaining. Record the mass. • Calculate and record the mass of FA 4 used. • Calculate and record the temperature rise. I II III IV[4]
- (b)(i)Calculate the energy produced during this reaction. (Assume that 4.2 J are needed to raise the temperature of 1.0 cm³ of solution by 1.0°C.) energy produced = ...................................... J [1][1]
- (b)(ii)Calculate the number of moles of MgO used. moles of MgO = ...................................... mol [1][1]
- (b)(iii)Calculate the enthalpy change, in kJ mol⁻¹, for the reaction below. MgO(s) + 2HCl(aq) → MgCl2(aq) + H2O(l) enthalpy change = ...................................... kJ mol⁻¹ [1] sign value[1]
- (c)By means of a calculation, use your answer to 1(c)(iv) to show that the hydrochloric acid, FA 2, was in excess for the reaction in 2(a). (If you were unable to carry out the calculation in 1(c)(iv), you should assume that the concentration of HCl in FA 2 is 3.75 mol dm⁻³. This may not be the correct value.) [1][1]
- (d)(i)Method • Support the second plastic cup in the 250 cm³ beaker. • Use the measuring cylinder to transfer 40 cm³ of FA 2 into the plastic cup. • Measure and record the initial temperature of the solution. • Weigh the container with FA 5. Record the mass. • Add approximately half of the FA 5 from the container to the FA 2 in the plastic cup. • Stir constantly for approximately 30 seconds. • Then add the remainder of the FA 5. • Stir constantly until the maximum temperature is reached. • Measure and record the maximum temperature. • Weigh the container with any FA 5 remaining. Record the mass. • Calculate and record the mass of FA 5 used. • Calculate and record the temperature rise. [2][2]
- (d)(ii)Apart from the change in temperature, what observations did you make during the reaction? [1][1]
- (d)(iii)Calculation Calculate the enthalpy change for this reaction. MgCO3(s) + 2HCl(aq) → MgCl2(aq) + CO2(g) + H2O(l) enthalpy change = ...................................... kJ mol⁻¹ [1] sign value[1]
- (e)Use your values for the enthalpy changes calculated in (b)(iii) and (d)(iii) to calculate the enthalpy change for the reaction below. (If you were unable to calculate the enthalpy changes, assume that the magnitude of the enthalpy change in (b)(iii) is 110.3 kJ mol⁻¹ and the magnitude of the enthalpy change in (d)(iii) is 65.9 kJ mol⁻¹. Note: these may not be the correct magnitudes and the signs have been deliberately omitted.) MgO(s) + CO2(g) → MgCO3(s) enthalpy change = ...................................... kJ mol⁻¹ [1] sign value[1]
- (f)Outline one improvement to the method that would lead to more accurate values for the enthalpy changes. Do not include a change to the apparatus used, such as the use of a lid. [1][1]
- (g)Give the error in a single balance reading. error = ± ...................................... g Which is greater, the percentage error in the mass of magnesium oxide used or the percentage error in the mass of magnesium carbonate used? Percentage error is greater in ...................................... Calculate the greater percentage error. greater % error = ...................................... % [2][2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.
- [1] I Suitable tables/lists with values entered in the space provided. • Three clearly labelled masses (do not allow 'weight') with correct units • Three unambiguous labelled temperatures, with units
- [1] II Readings and subtraction in 2(a) and 2(d) • All four measured temperatures recorded to .0 or .5 °C • Both temperature changes correctly subtracted.
- [2] Accuracy marks Round all thermometer readings to 0.5 °C. Check the candidate's and supervisor's subtractions and compare the candidate's [corrected] temperature rise with the supervisor's. The difference between candidate and supervisor is δ. See table below for marks available. Sup ΔTmax > 40.0 °C (1 mark: δ ≤ 5.0 °C, 2 marks: δ ≤ 2.5 °C) Sup ΔTmax 30.5-40.0 °C (1 mark: δ ≤ 4.0 °C, 2 marks: δ < 2.0 °C) Sup ΔTmax 20.5-30.0 °C (1 mark: δ ≤ 3.0 °C, 2 marks: δ < 1.5 °C) Sup ΔTmax 10.5-20.0 °C (1 mark: δ < 2.0 °C, 2 marks: δ < 1.0 °C) Sup ΔTmax 5.5-10.0 °C (1 mark: δ < 1.0 °C, 2 marks: δ ≤ 0.5 °C) Sup ΔTmax < 5.5 °C (1 mark: δ ≤ 0.5 °C, 2 marks: not available) • All masses in (a) and (d) recorded to one or more d.p. (balance readings must be consistent d.p. within each experiment) • Both masses correctly subtracted.
- [1] Correctly calculates heat change Heat change = 40 × 4.2 × temp rise AND Answer is correct to 2-4 s.f.
- [1] Correctly calculates number of moles of MgO No. of moles of MgO used = mass used/40.3 AND Answer is correct to 2-4 s.f.
- [1] Correctly uses (i)/(ii) and negative sign shown Enthalpy change = -(b)(i)/(b)(ii) × 1/1000 AND Answer is given to 2-4 s.f.
- [1] Correct expression(s) shown in 'excess' calculation Candidate must compare the number of moles of MgO and HCl used and correctly use the mole ratio of 1:2. Example of working No. of moles of HCl used = 0.04 × ans 1(c)(iv) (or n = 0.04 × 3.75 = 0.15) Maximum no. moles MgO that can be used = 0.5 × n Note – there are other valid ways of doing this calculation.
- [1] Readings written in space provided • Two thermometer readings are recorded both above 10 °C • Two masses are recorded giving mass of MgCO3 between 2-5 g.
- [1] Accuracy mark Check temperature subtractions of candidate and of supervisor. Compare the [corrected] candidate's temperature rise with the supervisor's. The difference is δ. • If δ is less than or equal to 2.0 °C, award the mark
- [1] Observations (two required) Fizzing / bubbles / effervescence AND either solid dissolves / disappears / colourless solution formed or reaction is brisk / rapid / vigorous / violent
- [1] Correct expression(s) for enthalpy change, with negative sign Enthalpy change = -40 × 4.2 × temp rise × 84.3/ mass MgCO3 ×1/1000
- [1] Enthalpy change correctly calculated with correct sign Answer = (b)(iii) – (d)(iii) and to minimum 2 s.f. unless answer is an integer. If default values are used, the answer must be -44.4 kJ mol⁻¹.
- [1] Plot a cooling curve (after the maximum temperature reached) OR plot a graph to get better value of ΔT OR use increased masses of FA 4 and / or FA 5 / mass of solid (added) OR heat the acid before adding solid / FA 4 and / or FA 5 Ignore answers related to the apparatus used.
- [1] Correct single reading error (see below) and MgO has the greater % error (Allow MgCO3 if this was the smaller mass.) If candidate used a 1 d.p. balance for this solid, error is 0.05 or 0.1 g If candidate used a 2 d.p. balance for this solid, error is 0.005 or 0.01 g If candidate used a 3 d.p. balance for this solid, error is 0.0005 or 0.001 g
- [1] Correct calculation of % error for MgO % error = 2 × (single error/mass of MgO used) × 100
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