Solid potassium halides react with concentrated sulfuric acid, according to the following equations. reaction 1 2KCl + H2SO4 → K2SO4 + 2HCl reaction 2 2KBr + 2H2SO4 → K2SO4 + SO2 + Br2 + 2H2O reaction 3 8KI + 5H2SO4 → 4K2SO4 + H2S + 4I2 + 4H2O What is the largest change in the oxidation number of sulfur in each of these reactions?
✓ Correct answer
C: 0 (reaction 1), 2 (reaction 2), 8 (reaction 3)
Practise more questions on this topic
Oracle Prep sorts past-paper questions by topic, so you can drill Electrochemistry and see which topics are most likely to come up next.
Sign up free →