The volume of ammonia produced against time is measured in two experiments. N2(g) + 3H2(g) ⇌ 2NH3(g) ∆H = −92 kJ mol⁻¹ In experiment 1, 3 mol of H2(g) and 1 mol of N2(g) react together at 45°C and a pressure of 200 atm. A graph showing the volume of ammonia produced against time is plotted. Experiment 2 is then performed. Experiment 2 differs from experiment 1 in one condition only. [Figure 13.1] How does experiment 2 differ from experiment 1?
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The correct answer is D. This question tests the candidate's understanding of reaction kinetics within the Chemistrysyllabus. The examiner's mark scheme requires...
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