A-LevelChemistryReaction kinetics9701/12 · May/June 2024 · Q131 Mark
The volume of ammonia produced against time is measured in two experiments. N2(g) + 3H2(g) ⇌ 2NH3(g) ∆H = −92 kJ mol⁻¹ In experiment 1, 3 mol of H2(g) and 1 mol of N2(g) react together at 45°C and a pressure of 200 atm. A graph showing the volume of ammonia produced against time is plotted. Experiment 2 is then performed. Experiment 2 differs from experiment 1 in one condition only. [Figure 13.1] How does experiment 2 differ from experiment 1?
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
AAn iron catalyst is present in experiment 2.
B2 mol of helium gas is present in the reaction mixture in experiment 2.
Cpressure of 250 atm is used in experiment 2.
Dtemperature of 600 °C is used in experiment 2.
✓ Correct answer
D: temperature of 600 °C is used in experiment 2.
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