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A-LevelChemistryEquilibria9701/51 · May/June 2023 · Q19 Marks

The partition coefficient, Kpc, shows the distribution of a solute between two immiscible solvents. Kpc is determined by measuring the concentration of the solute in each solvent. The organic solvent ethoxyethane, CH3CH2OCH2CH3, and water are immiscible. A student is asked to find Kpc of butanedioic acid, HOOCCH2CH2COOH, between ethoxyethane and water. The expression for Kpc when butanedioic acid is in equilibrium between ethoxyethane and water is shown. Kpc = [HOOCCH2CH2COOH(ethoxyethane)] [HOOCCH2CH2COOH(aq)] [density: ethoxyethane, 0.71gcm¯³; water, 1.00gcm-³] The student uses the following method to find the partition coefficient. A diagram of the apparatus is shown in [Figure 1.1]. step 1 Add 30.0cm³ of distilled water to a separating funnel. step 2 Weigh by difference 2.81 g of butanedioic acid into the separating funnel. step 3 Stopper the separating funnel and shake it until the butanedioic acid has dissolved. step 4 Remove the stopper and add 30.0cm³ of ethoxyethane to the separating funnel. step 5 Replace the stopper and shake the separating funnel gently. step 6 Place the separating funnel into a clamp. Allow the liquids to settle so that the two layers can be seen. step 7 Remove the stopper and open the separating funnel tap to allow the lower layer to run into a beaker labelled A. Run the upper layer into a beaker labelled B. step 8 Transfer 10.0cm³ of the aqueous layer into a conical flask. Titrate with 0.500moldm-3 NaOH(aq). Use thymolphthalein as the indicator. step 9 Take 10.0cm³ of the ethoxyethane layer and add 10.0cm³ of water to it. Titrate this mixture with 0.100 moldm¯³ NaOH(aq). Use thymolphthalein as the indicator.

  1. (a)(i)State whether beaker A in step 7 contains the aqueous layer or the ethoxyethane layer. Explain your answer. Beaker A contains the ........................................................... layer. explanation ................................................................................................................................................................................................................................................................................................[1]
  2. (a)(ii)Identify the piece of apparatus that should be used in step 8 to transfer 10.0cm³ of the aqueous layer.[1]
  3. (a)(iii)Suggest why water is added to the ethoxyethane layer in step 9 before the titration can take place.[1]
  4. (b)(i)For a 2.81 g sample of butanedioic acid, the titre for the aqueous layer is 27.25cm³ and the titre for the ethoxyethane layer is 22.50 cm³. The equation for the reaction between butanedioic acid and sodium hydroxide is shown. HOOCCH2CH2COOH + 2NaOH → NaOOCCH2CH2COONa + 2H2O Calculate the concentration of butanedioic acid in the aqueous layer. concentration of butanedioic acid = .............................................. moldm-3[1]
  5. (b)(ii)Calculate the partition coefficient, Kpc. Kpc = ..............................................................[2]
  6. (b)(iii)Explain why the student is only able to repeat the titration in step 8 once.[1]
  7. (b)(iv)Suggest how you would modify the procedure to ensure the student can repeat the titration in step 8 more than once.[1]
  8. (b)(v)A different student forgets to shake the separating funnel in step 5. Describe the effect this would have on the calculated Kpc value. Explain your answer. effect on Kpc ................................................................................................................................................................................................................................................................................................ explanation ................................................................................................................................................................................................................................................................................................[1]

This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.

Mark scheme

Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.

  1. [1] aqueous AND water has greater density (than ethoxyethane so it forms the lower layer)
  2. [1] (10 cm³) (volumetric) pipette
  3. [1] the acid transfers / dissolves into the water (before titration / reaction with sodium hydroxide)
  4. [1] n (NaOH) in titre = 27.25/1000 ×0.5 (= 0.0136250) n(HOOCCH2CH2COOH(aq)) = 0.0136250 / 2 = 0.0068125 [HOOCCH2CH2COOH(aq)] = ((27.25/1000)×0.5 / 2) x (1000/10) = 0.6813 mol dm⁻³ (0.68125 mol dm⁻³) at least 2 significant figures
  5. [2] M1 [HOOCCH2CH2COOH(ethoxyethane)] = 0.1125 mol dm⁻³ (22.50 × 0.1/1000 ÷ 10 / 1000)/2) M2 Kpc = M1 / (b)(i) Expected answer = 0.1125/0.68125 = 0.165(1376) (0.1614–0.1662) at least 2 significant figures
  6. [1] it is not possible to pipette all (30 cm³) of the aqueous layer from the beaker (as some will always be left behind)
  7. [1] use a larger volume (>30cm³) of water (in step 1)
  8. [1] Kpc value would be smaller / decrease AND because (equilibrium had not been attained and) more butanedioic acid remains in aqueous layer

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About this question

Topic
Equilibria, A-Level Chemistry (syllabus 9701). Structured question, 9 marks.
Source
A-Level Chemistry, May/June 2023 Paper 5 Variant 1, question 1.

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