LiAlH₄ contains AlH₄⁻ ions in which aluminium has an oxidation state of +3. LiAlH₄ reacts with water, as shown. LiAlH₄ + 4H₂O → 4H₂ + LiOH + Al(OH)₃ In this reaction, each of the four water molecules produces one hydroxide ion. It does this by losing one H⁺ ion, which reacts with the LiAlH₄. Which changes in oxidation number occur in this reaction?
✓ Correct answer
C: H increases by 1 and also decreases by 1.
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