Metal carbonates react with acid to produce carbon dioxide. You will determine the identity of a Group 2 metal M in a carbonate of formula MCO3 by reacting the carbonate with excess dilute hydrochloric acid and measuring the volume of carbon dioxide produced. MCO3(s) + 2HCl(aq) → MCl2(aq) + CO2(g) + H₂O(I) FA 1 is 50 cm³ of 4.00 moldm⁻³ hydrochloric acid, HCl. FA 2 is the metal carbonate, MCO3.
✓ Correct Answer
The correct answer is —. This question tests the candidate's understanding of atoms, molecules and stoichiometry within the Chemistrysyllabus. The examiner's mark scheme requires...
📋 Examiner Report & Trap Analysis
Common mistake: 62% of candidates selected the distractor because they confused... The examiner specifically designed this question to test whether students can differentiate between... To secure full marks, candidates must demonstrate...
Unlock the Examiner's Answer
Sign up for free to reveal the correct answer, the official mark scheme breakdown, and the examiner trap analysis for this question.
Sign Up Free to Unlock →Join thousands of Cambridge students already using Oracle Prep