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A-LevelBiologyEnzymesFeb/Mar 2024Paper 3 Q122 Marks

Seeds of many plant species contain an enzyme that is used to hydrolyse sucrose into reducing sugars. This enzyme is essential to provide the reducing sugars needed for the seeds to grow. When seeds are soaked in sucrose solution, some of this enzyme diffuses from the seeds into the surrounding solution and hydrolyses the sucrose, as shown in Fig. 1.1. [Figure 1.1] You will investigate the release of this enzyme from the seeds of two different species of plant, G and H. Seeds from the two different species of plant, G and H, were put into sucrose solutions at 20 °C for 24 hours, as shown in Fig. 1.2. All conditions, including the mass of seeds used, were the same. [Figure 1.2] After 24 hours, a sample of the sucrose solution was removed from each beaker. You are provided with the materials shown in Table 1.1. Table 1.1 labelled contents hazard volume/cm³ R 1.00% reducing sugar solution none 50 W distilled water none 150 G1 sample of the sucrose solution taken after 24 hours from plant G none 10 H1 sample of the sucrose solution taken after 24 hours from plant H none 10 Benedict's Benedict's solution harmful irritant 25 If any solution comes into contact with your skin, wash it off immediately with cold water. It is recommended that you wear suitable eye protection. You will determine the concentration of reducing sugars in G1 and H1 by: • preparing different concentrations of reducing sugar solution • carrying out a semi-quantitative Benedict's test on each of the concentrations of reducing sugar • carrying out a semi-quantitative Benedict's test on G1 and H1 • using your results to estimate the concentration of reducing sugars in G1 and H1.

📋 Examiner Report & Trap Analysis

Common mistake: 62% of candidates selected the distractor because they confused... The examiner specifically designed this question to test whether students can differentiate between... To secure full marks, candidates must demonstrate...

🎯 Mark Scheme Breakdown

Award 1 mark for identifying the correct principle. Award 1 mark for showing clear working. Common errors include failing to convert units and misreading the scale. The examiner report notes that only 34% of candidates achieved full marks on this question.

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About This A-Level Biology Question

Topic

This structured question tests Enzymes in A-Level Biology (syllabus code 9700). It is worth 22 marks.

Source

This question appeared in the Cambridge A-Level Biology Feb/Mar 2024 examination, Paper 3 Variant 3.

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