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A-LevelBiologyImmunity9700/42 · Feb/Mar 2019 · Q317 Marks

During an immune response, only B-lymphocytes with receptors that are specific to the antigens present are activated. Activation occurs when an antigen binds to a receptor of a B-lymphocyte. Activated B-lymphocytes grow in size and then divide by mitosis. Many further mitotic cell divisions occur, increasing the number of B-lymphocytes with receptors specific to the antigen. Eventually, cells produced in this process will develop into either plasma cells that secrete antibodies or memory B-cells. [Figure 3.1] is a summary of B-lymphocyte activation and the events that follow. The development of plasma cells and memory B-cells in this process depends on transcription factors.

  1. (a)Explain the role of transcription factors in gene expression in eukaryotic cells.[3]
  2. (b)Transcription factors are proteins. Genes that code for proteins can become mutated. Describe how different types of gene mutation can cause changes in the protein that is synthesised.[5]
  3. (c)BLIMP-1 is a transcription factor that is essential for the development of plasma cells and memory B-cells in the process shown in [Figure 3.1]. BLIMP-1 reduces the synthesis of c-Myc in B-lymphocytes. c-Myc is a protein that is required for the mitotic cell cycle to continue. Suggest and explain how a mutation in the gene coding for BLIMP-1 can prevent the development of plasma cells and memory B-cells.[3]
  4. (d)(i)Microarrays can be used to analyse the effect of transcription factors, such as BLIMP-1, on gene expression. Describe how a microarray is used in the study of gene expression.[4]
  5. (d)(ii)BCL6 is another transcription factor found in B-lymphocytes. The effect of BCL6 on gene expression was compared in two samples of B-lymphocytes. • Sample 1 consisted of B-lymphocytes that were producing BCL6. • Sample 2 consisted of B-lymphocytes that were not producing BCL6. Suggest why a microarray is suitable for identifying the function of the transcription factor BCL6 in these two samples.[2]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2019). The mark or mark type is shown in brackets.

  1. [3] any three from: 1 binds to DNA ; 2 at, promoter/enhancer ; 3 allows, RNA polymerase / other transcription factors, to bind (to, DNA / gene / promoter) ; 4 regulates / initiates / inhibits, gene expression / transcription; 5 A switches genes, on / off (so that genes are expressed) at the correct time / in the correct context / in the correct cell type / in the correct order ;
  2. [5] any five from: 1 base substitution / mis-sense mutation; 2 changes, triplet / codon; 3 base, deletion / insertion; 4 (results in) frame shift / description; 5 change in, protein primary structure / amino acid sequence ; 6 protein folds incorrectly / changes tertiary or 3-D structure ; 7 changes protein function / prevents protein function / makes protein unstable; 8 idea of new STOP codon; 9 only, short/first part of /no, protein is produced ;
  3. [3] any three from: 1 BLIMP-1, is not synthesised / is non-functional / has changed function ; 2 expression of the c-Myc gene, is not reduced / continues ; 3 synthesis / concentration, of c-Myc (protein), is maintained / increases ; 4 (B-lymphocytes continue to) divide by mitosis / proliferate ; A clonal expansion 5 differentiation / specialisation, prevented ;
  4. [4] any four from: 1 mRNA extracted from cells (of interest); 2 (mRNA) used (as template) to synthesise cDNA; 3 cDNA is tagged with a fluorescent dye ; 4 (fluorescent) cDNA, binds to / hybridises with, probe ; 5 each probe is unique to a different gene / AW ; 6 fluorescence indicates gene is expressed ; 7 AVP; e.g. detail of probe / use of UV light
  5. [2] any two from: 1 BCL6/transcription factors, regulate expression of genes ; 2 (microarray) can detect expression of genes ; 3 idea of difference in, fluorescence / gene expression, between two samples ; 4 difference in gene expression indicates regulation by BCL6 ;

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About this question

Topic
Immunity, A-Level Biology (syllabus 9700). Structured question, 17 marks.
Source
A-Level Biology, Feb/Mar 2019 Paper 4 Variant 2, question 3.

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