In this question all lengths are in centimetres. The volume of a cone of height h and base radius r is given by V = ⅓πr²h. It is known that sin (π/12) = (√6 - √2)/4, cos (π/12) = (√6 + √2)/4, tan (π/12) = 2 - √3. A water cup is in the shape of a cone with its axis vertical. The diagrams show the cup and its cross-section. The vertical angle of the cone is π/6 radians. The depth of water in the cup is h. The surface of the water is a circle of radius r. [Figure 12.1]
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