Mensuration Masterclass: Cones, Spheres & Composite Shapes

What is the biggest trap in composite surface area questions?
Table of Contents
Mensuration (3D Geometry) usually appears on Paper 2 as a massive 8-to-10 mark question. It terrifies students because of the complex formulas, but the secret is that CAIE gives you the hardest formulas on the paper! You just need to know how to deploy them. This guide from our Ultimate O-Level Mathematics Guide decodes the system.
1. The Two Heights of a Cone
A cone has two height measurements. Mixing them up guarantees zero marks.
- Vertical Height (h): The straight drop from the tip to the center of the base. It is used ONLY for finding Volume (V = ⅓πr²h).
- Slant Height (l): The diagonal length along the outer curve. It is used ONLY for finding the Curved Surface Area (CSA = πrl).
If the examiner gives you one, but you need the other, use Pythagoras' theorem. A right-angled triangle is formed inside the cone where the radius (r) and vertical height (h) are the sides, and the slant length (l) is the hypotenuse: r² + h² = l².
2. The Hemisphere Trap
The formula for the surface area of a full sphere is 4πr². So, what is the surface area of a solid hemisphere (half a sphere)?
If you said 2πr², you fell for the trap.
Total Surface Area of a Solid Hemisphere = 3πr²
When you cut a sphere in half, you do halve the curved outside shell (4πr² ÷ 2 = 2πr²). But you also expose a brand new flat circular base on the bottom. To find the TOTAL surface area, you must add the area of that new flat circle (πr²).
2πr² (curved shell) + πr² (flat base) = 3πr².
3. Worked Composite Shape Question
Question:
A solid is formed by a cone sitting exactly on top of a cylinder. The cylinder has radius 4 cm and height 10 cm. The cone has a slant height of 5 cm. Calculate the total surface area of the resulting solid.
Step 1 — Identify Exposed Surfaces
We need to paint the outside of this object. What surfaces get painted? 1. The curved surface of the cone (πrl). 2. The curved surface of the cylinder (2πrh). 3. The flat circular bottom base of the cylinder (πr²). We do NOT paint the bottom of the cone or the top of the cylinder — they are stuck together inside.
Step 2 — Calculate Area 1 (Cone Curve)
CSA = π × r × l
CSA = π × 4 × 5 = 20π
Step 3 — Calculate Area 2 (Cylinder Curve)
CSA = 2 × π × r × h
CSA = 2 × π × 4 × 10 = 80π
Step 4 — Calculate Area 3 (Cylinder Base)
Base Area = π × r²
Base Area = π × 4² = 16π
Step 5 — Add Total
Total Area = 20π + 80π + 16π = 116π
Total Area = 116 × 3.14159... = 364.4 cm² (to 1 d.p.)
Frequently Asked Questions
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